Product Code Database
Example Keywords: strategy games -mobile $97-133
   » » Wiki: Optical Theorem
Tag Wiki 'Optical Theorem'.
Tag

Optical theorem
 (

 C O N T E N T S 

In , the optical theorem is a general law of scattering theory, which relates the zero-angle scattering amplitude to the total cross section of the scatterer. It is usually written in the form

\sigma=\frac{4\pi}{k}~\mathrm{Im}\,f(0),
where (0) is the scattering amplitude with an angle of zero, that is the amplitude of the wave scattered to the center of a distant screen and is the in the incident direction.

Because the optical theorem is derived using only conservation of energy, or in quantum mechanics from conservation of probability, the optical theorem is widely applicable and, in quantum mechanics, \sigma_\mathrm{tot} includes both elastic and inelastic scattering.

The generalized optical theorem, first derived by Werner Heisenberg, follows from the unitary condition and is given byLandau, L. D., & Lifshitz, E. M. (2013). Quantum mechanics: non-relativistic theory (Vol. 3). Elsevier.

f(\mathbf{n},\mathbf{n}') -f^*(\mathbf{n}',\mathbf{n})= \frac{ik}{2\pi} \int f(\mathbf{n},\mathbf{n} )f^*(\mathbf{n}',\mathbf{n})\,d\Omega''
where f(\mathbf{n},\mathbf{n}') is the scattering amplitude that depends on the direction \mathbf{n} of the incident wave and the direction \mathbf{n}'of scattering and d\Omega is the differential . When \mathbf{n}=\mathbf{n}', the above relation yields the optical theorem since the left-hand side is just twice the imaginary part of f(\mathbf{n},\mathbf{n}) and since \sigma=\int|f(\mathbf{n},\mathbf{n} )|^2\,d\Omega. For scattering in a centrally symmetric field, f depends only on the angle \theta between \mathbf{n} and \mathbf{n}', in which case, the above relation reduces to
\mathrm{Im} f(\theta)=\frac{k}{4\pi}\int f(\gamma)f(\gamma')\,d\Omega''
where \gamma and \gamma' are the angles between \mathbf{n} and \mathbf{n}' and some direction \mathbf{n}''.


History
The optical theorem was originally developed independently by Wolfgang SellmeierThe original publication omits his first name, which however can be inferred from a few more publications contributed by him to the same journal. One web source says he was a former student of Franz Ernst Neumann. Otherwise, little to nothing is known about Sellmeier. and Lord Rayleigh in 1871.Strutt, J. W. (1871). XV. On the light from the sky, its polarization and colour. The London, Edinburgh, and Dublin Philosophical Magazine and Journal of Science, 41(271), 107-120. Lord Rayleigh recognized the zero-angle scattering amplitude in terms of the index of refraction as
n = 1 + 2\pi \frac{Nf(0)}{k^2}
(where is the number density of scatterers), which he used in a study of the color and polarization of the sky.

The equation was later extended to quantum scattering theory by several individuals, and came to be known as the Bohr–Peierls–Placzek relation after a 1939 paper. It was first referred to as the "optical theorem" in print in 1955 by and Frederic de Hoffmann, after it had been known as a "well known theorem of optics" for some time.


Derivation
The theorem can be derived rather directly from a treatment of a scalar . If a is incident along positive z axis on an object, then the wave scattering amplitude a great distance away from the scatterer is approximately given by

\psi(\mathbf{r}) \approx e^{ikz}+f(\theta)\frac{e^{ikr}}{r}.

All higher terms, when squared, vanish more quickly than 1/r^2, and so are negligible a great distance away. For large values of z and for small angles, a gives us

r=\sqrt{x^2+y^2+z^2}\approx z+\frac{x^2+y^2}{2z}.

We would now like to use the fact that the intensity is proportional to the square of the amplitude \psi. Approximating 1/r as 1/z, we have

\begin{align}
   |\psi|^2 &\approx \left|e^{ikz}+\frac{f(\theta)}{z}e^{ikz}e^{ik(x^2+y^2)/2z}\right|^2 \\
            &= 1+\frac{f(\theta)}{z}e^{ik(x^2+y^2)/2z}+\frac{f^*(\theta)}{z}e^{-ik(x^2+y^2)/2z}+\frac{|f(\theta)|^2}{z^2}.
   \end{align}
     

If we drop the 1/z^2 term and use the fact that c+c^*=2\operatorname{Re}{c}, we have

|\psi|^2 \approx 1+2\operatorname{Re}{\left\frac{f(\theta)}{z}e^{ik(x^2+y^2)/2z}\right}.

Now suppose we over a screen far away in the xy plane, which is small enough for the small-angle approximations to be appropriate, but large enough that we can integrate the intensity over -\infty to \infty in x and y with negligible error. In , this is equivalent to summing over many fringes of the pattern. By the method of stationary phase, we can approximate f(\theta)=f(0) in the below integral. We obtain

\int |\psi|^2\,dx\,dy \approx A +2\operatorname{Re}\left\frac{f(0)}{z}\int_{-\infty}^{\infty},

where A is the area of the surface integrated over. Although these are improper integrals, by suitable substitutions the exponentials can be transformed into complex Gaussians and the definite integrals evaluated resulting in:

\begin{align}
   \int |\psi|^2\,da &= A + 2\operatorname{Re}\left[\frac{f(0)}{z}\,\frac{2\pi i z}{ k}\right] \\
                     &= A - \frac{4\pi}{k}\,\operatorname{Im}[f(0)].\end{align}
     

This is the probability of reaching the screen if none were scattered, lessened by an amount (4\pi/k)\operatorname{Im}f(0), which is therefore the effective scattering cross section of the scatterer.


See also

  • (1999). 047130932X, Hamilton Printing Company. 047130932X

Page 1 of 1
1
Page 1 of 1
1

Account

Social:
Pages:  ..   .. 
Items:  .. 

Navigation

General: Atom Feed Atom Feed  .. 
Help:  ..   .. 
Category:  ..   .. 
Media:  ..   .. 
Posts:  ..   ..   .. 

Statistics

Page:  .. 
Summary:  .. 
1 Tags
10/10 Page Rank
5 Page Refs
1s Time